(x^3-8)/(x-2)

.

$${\frac{\left({{\mathtt{x}}}^{{\mathtt{3}}}{\mathtt{\,-\,}}{\mathtt{8}}\right)}{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{2}}\right)}} = {\frac{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{2}}\right){\mathtt{\,\times\,}}\left({{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\right)}{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{2}}\right)}}$$

 

= x² +2x +4