(x^3 + x^2*a + x + b)/ x^2 - 4

(x^3 + x^2*a + x + b)/ x^2 - 4 

$$if \;\;lim(f(x))\Rightarrow 5\;\; with \;\;x\Rightarrow 2$$

This is what I think :/

$$\\\displaystyle\lim_{x\rightarrow2}\;\frac{x^3+ax^2+x+b}{x^2-2}=5\\\\ \displaystyle\lim_{x\rightarrow2}\;\frac{x^3+ax^2+x+b}{x^2-2}*(x-2)=\displaystyle\lim_{x\rightarrow2}\;5(x-2)\\\\ \displaystyle\lim_{x\rightarrow2}\;\frac{x^3+ax^2+x+b}{x+2}=\displaystyle\lim_{x\rightarrow2}\;5x-10\\\\ \displaystyle\lim_{x\rightarrow2}\;x^3+ax^2+x+b=\displaystyle\lim_{x\rightarrow2}\;(5x-10)(x+2)\\\\ 8+4a+2+b=0\\\\ 4a+b=-10$$