$${\frac{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{7}}\right)}{\left({\mathtt{9}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}} = {\frac{{\mathtt{5}}}{{\mathtt{12}}}}$$
Cross multiply and you will get:
$$12x-84=45x$$
After you get the above just solve for x:
$$-84=33x$$
$$x=-2.5454545454545455$$
So your answer is x=-2.5454545454545455. You can simply that down further to a number like -2.55.
$${\frac{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{7}}\right)}{\left({\mathtt{9}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}} = {\frac{{\mathtt{5}}}{{\mathtt{12}}}}$$
Cross multiply and you will get:
$$12x-84=45x$$
After you get the above just solve for x:
$$-84=33x$$
$$x=-2.5454545454545455$$
So your answer is x=-2.5454545454545455. You can simply that down further to a number like -2.55.
Excellent answer, chilledz3non......"thumbs-up" from me...
Note something.....x = -84/33 = -28/11.......we could also leave the answer in this form....some people like the "exact" answer, rather than a repeating decimal....I'm actually indifferent, but I might be in the minority......
I definitely prefer exact answers
But I don't like improper fractions much. I think that they should be presented as mixed numberals.
If you were able to use the repeating dot notation for a decimal that would also be fine to because that is exact.
A note to anon.
Chris has probably answered the question that you intended to ask BUT
this is the question that you did ask.
x-7/9x=5/12
$$\begin{array}{rll}
x-\frac{7}{9}x&=&\frac{5}{12}\\\\
\frac{2x}{9}&=&\frac{5}{12}\\\\
36\times \frac{2x}{9}&=&36\times \frac{5}{12}\\\\
8x&=&15\\\\
x&=&\frac{15}{8}\\\\
x&=&1\frac{7}{8}\\\\
\end{array}$$