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x^-8=sqrt(20000)

 

How do i solve it?

 Nov 4, 2015

Best Answer 

 #1
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x^-8=sqrt(20000)

How do i solve it?

 

\(\small{ \begin{array}{rcll} x^{-8} &=& \sqrt{20000} \\ x^{-8} &=& 20000^{\frac12} \qquad | \qquad ()^{\frac{1}{-8}}\\ x^{\frac{-8}{-8}} &=& 20000^{\frac{1}{-8\cdot 2}} \\ x &=& 20000^{\frac{1}{-16}} \\ x &=& \frac{1}{20000^{\frac{1}{16}}} \\ x &=& 0.5384998979 \end{array} }\)

 

laugh

 Nov 4, 2015
 #1
avatar+26400 
+25
Best Answer

x^-8=sqrt(20000)

How do i solve it?

 

\(\small{ \begin{array}{rcll} x^{-8} &=& \sqrt{20000} \\ x^{-8} &=& 20000^{\frac12} \qquad | \qquad ()^{\frac{1}{-8}}\\ x^{\frac{-8}{-8}} &=& 20000^{\frac{1}{-8\cdot 2}} \\ x &=& 20000^{\frac{1}{-16}} \\ x &=& \frac{1}{20000^{\frac{1}{16}}} \\ x &=& 0.5384998979 \end{array} }\)

 

laugh

heureka Nov 4, 2015
 #2
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0

x^-8=sqrt(20000)

x^8=141.4213

x=141.4213^1/8

x=1.8570

 Nov 4, 2015

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