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Solve: 6 cos2 x + 5 cos x = -1

 Mar 24, 2016

Best Answer 

 #1
avatar+128599 
+5

6 cos^2 x + 5 cos x = -1   add 1 to both sides

 

6 cos^2 x + 5 cos x  + 1 = 0         factor

 

(3cosx +1) (2cosx + 1)  = 0

 

Set each factor to 0

 

3cosx + 1  =  0                                           2cosx + 1 = 0

 

3cosx  = -1                                                  2cosx = -1

 

cosx = -1/3                                                   cosx  = -1/2

 

arccos (-1/3)  = about109.5° + n360°          arcos (-1/2)  =   120°  + n360°

 

And at  about     250.5” + n360°                and                     240 °  +  n360°   

 

Where n is an integer

 

Here's the graph, Shades :   https://www.desmos.com/calculator/knlolptzrg

 

 

 

cool cool cool                                 

 Mar 24, 2016
 #1
avatar+128599 
+5
Best Answer

6 cos^2 x + 5 cos x = -1   add 1 to both sides

 

6 cos^2 x + 5 cos x  + 1 = 0         factor

 

(3cosx +1) (2cosx + 1)  = 0

 

Set each factor to 0

 

3cosx + 1  =  0                                           2cosx + 1 = 0

 

3cosx  = -1                                                  2cosx = -1

 

cosx = -1/3                                                   cosx  = -1/2

 

arccos (-1/3)  = about109.5° + n360°          arcos (-1/2)  =   120°  + n360°

 

And at  about     250.5” + n360°                and                     240 °  +  n360°   

 

Where n is an integer

 

Here's the graph, Shades :   https://www.desmos.com/calculator/knlolptzrg

 

 

 

cool cool cool                                 

CPhill Mar 24, 2016

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