+26388 x/y=2 remainder 8
x=?
y=?
if x and y are integer and y > 8 :
\(\begin{array}{|rcll|} \hline n \in N \\ x &=& 8+2\cdot n \\ y &=& n \\ \hline \end{array} \)
\(\begin{array}{|r|l|l|r|c|} \hline n & x=8+2\cdot n & y = n & \frac{x}{y} & \text{quotient} & \text{remainder} \\ \hline 9 & x=8+2\cdot 9=26 & y = 9 & \frac{26}{9}& 2 & 8 \\ 10 & x=8+2\cdot 10=28 & y = 10 & \frac{28}{10}& 2 & 8 \\ 11 & x=8+2\cdot 11=30 & y = 11 & \frac{30}{11}& 2 & 8 \\ 12 & x=8+2\cdot 12=32 & y = 12 & \frac{32}{12}& 2 & 8 \\ 13 & x=8+2\cdot 13=34 & y = 13 & \frac{34}{13}& 2 & 8 \\ 14 & x=8+2\cdot 14=36 & y = 14 & \frac{36}{14}& 2 & 8 \\ \dots & \dots & \dots & \dots & \dots & \dots \\ \hline \end{array} \)
+37084 Infinite answers to this.....when you have TWO unknowns (x and y) you must have TWO equations to reach a single discrete answer for x and y.
68/30 = 2 remainder 8
+26388 x/y=2 remainder 8
x=?
y=?
if x and y are integer and y > 8 :
\(\begin{array}{|rcll|} \hline n \in N \\ x &=& 8+2\cdot n \\ y &=& n \\ \hline \end{array} \)
\(\begin{array}{|r|l|l|r|c|} \hline n & x=8+2\cdot n & y = n & \frac{x}{y} & \text{quotient} & \text{remainder} \\ \hline 9 & x=8+2\cdot 9=26 & y = 9 & \frac{26}{9}& 2 & 8 \\ 10 & x=8+2\cdot 10=28 & y = 10 & \frac{28}{10}& 2 & 8 \\ 11 & x=8+2\cdot 11=30 & y = 11 & \frac{30}{11}& 2 & 8 \\ 12 & x=8+2\cdot 12=32 & y = 12 & \frac{32}{12}& 2 & 8 \\ 13 & x=8+2\cdot 13=34 & y = 13 & \frac{34}{13}& 2 & 8 \\ 14 & x=8+2\cdot 14=36 & y = 14 & \frac{36}{14}& 2 & 8 \\ \dots & \dots & \dots & \dots & \dots & \dots \\ \hline \end{array} \)
