Two sides of a square lie on the straight lines:-
\[2x+3y+7=0\]
And
\[2x+3y+11=0\]
What is the area of the square?
We just need to find the distance between the lines ....this will be the side of the square
It's possible to derive this with a little work, but I prefer to use a formula to calculate the distance between parallel lines
We have the forms
Ax + By + C1 = 0
Ax + By + C2 = 0
The distance is given by
l C1 -C2 l l 7 - 11 l 4
_______________ = ______________ = ________
sqrt ( A^2 + B^2) sqrt ( 2^2 + 3^2) sqrt (13)
Area of the square = side^2 = ( 4/ sqrt (13) )^2 = 16/13 units^2