x+y+z+ø= 85

x+y+z+ø= 85

X=ø-4

y=x/8

z=x/9

 

 

       
\(x+y+z+\phi = 85\\ x=\phi-4\\ y=x/8=\frac{\phi-4}{8} \\ z=x/9=\frac{\phi-4}{9} \\~\\ so\\ \phi-4+\frac{\phi-4}{8} +\frac{\phi-4}{9} =85\\ 72\phi-4*72+72*\frac{\phi-4}{8} +72*\frac{\phi-4}{9} =72*85\\ 72\phi+9(\phi-4)+8(\phi-4) =72*85+4*72\\ 72\phi+17(\phi-4) =72*89\\ 72\phi+17\phi-68 =72*89\\ 89\phi =72*89+68\\ 89\phi =6476\\ \phi=\frac{6476}{89}\\ \text{Now just do the substitutions to get the other pronumerals}\\ \text{The sub the answers back in to check it is all correct.}\)