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x^2+y^2+16x−24y+159=0 .

What is the center of the circle?

Kakarot_15  May 2, 2017
edited by Kakarot_15  May 2, 2017
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x^2+y^2+16x−24y+159=0   

 

x^2 + 16x  + y^2 - 24y   =  -159        complete the square on x and y

 

x^2 + 16x  +  64  + y^2 - 24y  + 144   =   -159 + 64 + 144        factor

 

(x  +  8)^2   + (y - 12)^2   =  49

 

The center is  ( -8, 12 )

 

 

cool cool cool

CPhill  May 2, 2017

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