x^2+y^2+16x−24y+159=0 .
What is the center of the circle?
x^2+y^2+16x−24y+159=0
x^2 + 16x + y^2 - 24y = -159 complete the square on x and y
x^2 + 16x + 64 + y^2 - 24y + 144 = -159 + 64 + 144 factor
(x + 8)^2 + (y - 12)^2 = 49
The center is ( -8, 12 )