xover3-5=3(x-2)

$${\frac{{\mathtt{x}}}{{\mathtt{3}}}}{\mathtt{\,-\,}}{\mathtt{5}} = {\mathtt{3}}{\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{2}}\right)$$          | * 3

 

x-15=9x-18          =>   3= 8x       =>     x = $${\frac{{\mathtt{3}}}{{\mathtt{8}}}}$$

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