xover3-5=3(x-2)

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xover3-5=3(x-2)

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xover3-5=3(x-2)

Guest Jun 17, 2015

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${\frac{{\mathtt{x}}}{{\mathtt{3}}}}{\mathtt{\,-\,}}{\mathtt{5}} = {\mathtt{3}}{\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{2}}\right)$ | * 3

x-15=9x-18 => 3= 8x => x = ${\frac{{\mathtt{3}}}{{\mathtt{8}}}}$

radix Jun 17, 2015

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radix · Answer 1 · 2015-06-17T11:06:25

${\frac{{\mathtt{x}}}{{\mathtt{3}}}}{\mathtt{\,-\,}}{\mathtt{5}} = {\mathtt{3}}{\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{2}}\right)$ | * 3

x-15=9x-18 => 3= 8x => x = ${\frac{{\mathtt{3}}}{{\mathtt{8}}}}$

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xover3-5=3(x-2)

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x-15=9x-18 => 3= 8x => x = ${\frac{{\mathtt{3}}}{{\mathtt{8}}}}$

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x-15=9x-18 => 3= 8x => x = ${\frac{{\mathtt{3}}}{{\mathtt{8}}}}$

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xover3-5=3(x-2)

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x-15=9x-18 => 3= 8x => x = 38{\frac{{\mathtt{3}}}{{\mathtt{8}}}}

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x-15=9x-18 => 3= 8x => x = 38{\frac{{\mathtt{3}}}{{\mathtt{8}}}}

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x-15=9x-18 => 3= 8x => x = ${\frac{{\mathtt{3}}}{{\mathtt{8}}}}$

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x-15=9x-18 => 3= 8x => x = ${\frac{{\mathtt{3}}}{{\mathtt{8}}}}$