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hi how do i solve y=1(x-(-3))^3+0

 Jul 13, 2016
 #1
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+5

hi how do i solve y=1(x-(-3))^3+0

Expanded form:y = x^3+9x^2+27x+27= (x+3)^3

 Jul 13, 2016
 #2
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y=1(x-(-3))^3+0

 

\(y=1(x-(-3))^3+0\\ y=(x-(-3))^3\\ y=(x+3)^3\\ y=x^3+3*3x^2+3*3^2x+3^3\\ y=x^3+9x^2+27x+27\\\)

 Jul 13, 2016

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