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Problems with initials values y(0)=1, y'(1)=0 . The solution has the form Y=C1y1+C2y2+yp.

y"-4y'+4y'=(12x2-6x)(e2x)

SBonilla  May 10, 2018
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What method have you been taught to calculate a particular integral ?

Guest May 10, 2018

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