y-(-5)= 1/2(x-4)+ 3

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y-(-5)= 1/2(x-4)+ 3

Guest Sep 27, 2016

geno3141 · Answer 1 · 2016-09-27T02:09:16

What do you need to do with that equation?

Guest · Answer 2 · 2016-09-27T02:37:51

Well im just going to guess that you need to plug it in, if thats the case heres the work:

y-(-5)= 1/2(x-4)+ 3

y-(-5)= 1/2(-5-4)+ 3

y-(-5)= 1/2(-9)+ 3

y-(-5)= -4.5+ 3

y-(-5)= -1.5

then your point would be (-5,-1.5)