y=5-3x

Thanks, Anonymous...here's another way

Let x = 0   so we have

y = 5 -3(0)

y = 5 - 0

y = 5     .........so the point  (0, 5) is on the graph

Next, let y = 0   so we have

0 = 5 - 3x        add 3x to both sides

3x = 5         divide by 3 on both sides

x = 5/3       so the point (5/3, 0) is also on the graph

Plot both points and draw a line between them....there's your graph!!!!

See the graph here:  https://www.desmos.com/calculator/53iinbhbxy

First, you would have to change the equation into slope-intercept form which is defined as -

y=mx+b, where "m" stands for the slope of the line and "b" represents the y-intercept. You would do this by switching the places of the -3x and the 5 because the coeffiecent with x represents the slope. Slope is defined as ryse/run (rise over run). This means the slope is actually -3/1. Since the y-intercept is 5, you would put a point on the y-axis starting at 5. Then since slope means ryse/run, you would rise up three, and move to the left 1 and place a point there since the slope is negative. Then you would start at 5 again, but this time, you will go down three and right one because of the negative slope, and place a point there. Finally, you would connect the three points to make a line.