Solve the following system:
{y = 5 x - 13 | (equation 1)
5 x + 2 y = 19 | (equation 2)
Express the system in standard form:
{-(5 x) + y = -13 | (equation 1)
5 x + 2 y = 19 | (equation 2)
Add equation 1 to equation 2:
{-(5 x) + y = -13 | (equation 1)
0 x+3 y = 6 | (equation 2)
Divide equation 2 by 3:
{-(5 x) + y = -13 | (equation 1)
0 x+y = 2 | (equation 2)
Subtract equation 2 from equation 1:
{-(5 x)+0 y = -15 | (equation 1)
0 x+y = 2 | (equation 2)
Divide equation 1 by -5:
{x+0 y = 3 | (equation 1)
0 x+y = 2 | (equation 2)
Collect results:
Answer: x = 3 and y = 2
