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y+9=(x-4)^2

What is the vertex?

(4,9)?

-Hayley

 Nov 24, 2015
 #1
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K U may need to make a account or stop putting ur name cause im pretty sure ppl dont need to know ur name.

 Nov 24, 2015
 #2
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Omggoshh. Please calm down. I just want some help in math.

 Nov 24, 2015
 #3
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K but ppl dont need to know ur name

 Nov 24, 2015
 #4
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Okay.

 Nov 24, 2015
 #5
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(4, -9)

 Nov 24, 2015
 #6
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+5

Hayley.....  Actually, Melody has encouraged people to sign their names if they are posting as guests ... so no worries!

 

I get the vertex as   4 , -9     

 

  Did you try the graphing function of the calculator so you can look at it?

 

 

~jc

 Nov 24, 2015
 #7
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Do you mind me asking how you got that answer? just so i know how to do it next time. please and thank you! and i have not graphed it yet :) i always siggn my name at the bottom, and this girl keeps going off on me >:(

-Hayley

 Nov 24, 2015
 #8
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y + 9  =  (x - 4)^2

 

You have the x coordinate correct

 

Put it in this form, Hayley

 

y  = (x - h)^2  +  k

 

So we have.......  [subtracting 9 from both sides]

 

y = (x - 4)^ - 9

 

In this form.....the vertex can be read thusly, as  ....      (4 , -9)

 

In other words......the x coordinate of the vertex is the x value that makes x - 4  = 0  [this is 4[......   and the y coordinate  is just the last term and its associated sign.......

 

 

 

cool cool cool

 Nov 24, 2015
 #9
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Knowing this, Hayley.....can you find the vertex of

 

y - 8 =  (x + 3)^2          ????

 

 

cool cool cool

 Nov 24, 2015
 #10
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Awee C-r-a-p. i have to do the work! ok, one moment please

-Hayley

 Nov 24, 2015
 #11
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Hayley.......

 

Do you have a Facebook account????....If so......you should be able to use Facebook email to set up an account on here.......

 

 

 

cool cool cool

 Nov 24, 2015
 #12
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0

I am a foster child, so i cannot have any social media accounts 

-Hayley

 Nov 24, 2015
 #13
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0

yeahh.. so that's why.. :(

-Hayley

 Nov 24, 2015

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