Y is inversely proportional to the square of x
when y = 9 x = 1
Find the value of x when y = 16
what I did: 16= 9/x^2
y = k /x^2
We need to find k
And we know that
9 = k / 1 multiply both sides by 1
9 = k
So......when y = 16, we have
16 = 9 / x^2 rearrange as
x^2 = 9 /16 take the positive root
x = 3 / 4