Y is inversely proportional to the square of x

when y = 9 x = 1

Find the value of x when y = 16

what I did: 16= 9/x^2

y = k /x^2

We need to find k

And we know that

9 = k / 1 multiply both sides by 1

9 = k

So......when y = 16, we have

16 = 9 / x^2 rearrange as

x^2 = 9 /16 take the positive root

x = 3 / 4