y=−2x+12ˏy=2x+44 I assume you want to solve this system...
Set the "y's" equal.....so we have....
-2x + 12 =2x + 44 add 2x to both sides.....subtract 44 from both sides
-32 = 4x divide both sides by 4
-8 = x and substituting this into either equation, we can find y
So
y = 2(-8) + 44 = -16 + 44 = 28
And the solution set is (-8, 28)
y=−2x+12ˏy=2x+44 I assume you want to solve this system...
Set the "y's" equal.....so we have....
-2x + 12 =2x + 44 add 2x to both sides.....subtract 44 from both sides
-32 = 4x divide both sides by 4
-8 = x and substituting this into either equation, we can find y
So
y = 2(-8) + 44 = -16 + 44 = 28
And the solution set is (-8, 28)