Solve the following system:
{y = x+3
y = 4 x+12
Substitute y = x+3 into the second equation:
{y = x+3
x+3 = 4 x+12
In the second equation, look to solve for x:
{y = x+3
x+3 = 4 x+12
Subtract 4 x+3 from both sides:
{y = x+3
-3 x = 9
Divide both sides by -3:
{y = x+3
x = -3
Substitute x = -3 into the first equation:
{y = 0
x = -3
Collect results in alphabetical order:
Answer: | x = -3 and y=0
