We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
145
2
avatar

A ball is thrown into the air with an initial upward velocity of 48 ft/s. It height h in feet after t seconds is given by the function h (t) = – 16t2 + 48t + 4.

 

A) What height will the ball be when 2 seconds has passed?

 Feb 12, 2019
 #1
avatar+19811 
+2

t = time    Just put   t = 2 in to the equation and calculate  h

 

h = - 16(2^2) + 48(2) + 4         Got it ?cheeky

 Feb 12, 2019
 #2
avatar
0

Thank you for the help, I don't know why I missed something as simple as that.

Guest Feb 12, 2019

26 Online Users

avatar
avatar
avatar