A ball is thrown into the air with an initial upward velocity of 48 ft/s. It height h in feet after t seconds is given by the function h (t) = – 16t2 + 48t + 4.

A) What height will the ball be when 2 seconds has passed?

Guest Feb 12, 2019

#1**0 **

t = time Just put t = 2 in to the equation and calculate h

h = - 16(2^2) + 48(2) + 4 Got it ?

ElectricPavlov Feb 12, 2019