Rhombus ABCD has perimeter 148, and one of its diagonals has length 24. How long is the other diagonal?
First, find the length of a side. Since it is a rhombus, the side length is \(148/4=37\)
Applying the pythagorean theorem, we get half the diagonal squared plus half 24 squared equals the side length squared.
So \((\frac{1}{2}x)^2+12^2=37^2\) and half the diagonal is equal to \(35\)
Thus the diagonal is equal to \(35*2=70\)
First, find the length of a side. Since it is a rhombus, the side length is \(148/4=37\)
Applying the pythagorean theorem, we get half the diagonal squared plus half 24 squared equals the side length squared.
So \((\frac{1}{2}x)^2+12^2=37^2\) and half the diagonal is equal to \(35\)
Thus the diagonal is equal to \(35*2=70\)
