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# Yo need some help

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Rhombus ABCD has perimeter 148, and one of its diagonals has length 24. How long is the other diagonal?

Aug 26, 2018

#1
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First, find the length of a side. Since it is a rhombus, the side length is $$148/4=37$$

Applying the pythagorean theorem, we get half the diagonal squared plus half 24 squared equals the side length squared.

So $$(\frac{1}{2}x)^2+12^2=37^2$$ and half the diagonal is equal to $$35$$

Thus the diagonal is equal to $$35*2=70$$

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Aug 26, 2018

#1
+1

First, find the length of a side. Since it is a rhombus, the side length is $$148/4=37$$

Applying the pythagorean theorem, we get half the diagonal squared plus half 24 squared equals the side length squared.

So $$(\frac{1}{2}x)^2+12^2=37^2$$ and half the diagonal is equal to $$35$$

Thus the diagonal is equal to $$35*2=70$$

Guest Aug 26, 2018
#2
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Thanks!

Guest Aug 28, 2018