You and a friend are hiking in the mountains. You want to climb to a ledge that is 20ft above you. The height of the grappling hook you throw is given by the function h = - 16t2 – 32t + 5. a) What is the maximum height of the grappling hook? b) Can you throw it high enough to reach the ledge?
I think the function should be h = -16t^2 + 32t + 5
The position of the grappling hook at time 0 = 5 ft.
And the max height it reaches is 21 ft.....but it needs to reach a height of 25ft....so, no, it won't be thrown high enough to reach the ledge....
Here's a graph that substitutes y for h and x for t....
https://www.desmos.com/calculator/pzsjsonnv0
I think the function should be h = -16t^2 + 32t + 5
The position of the grappling hook at time 0 = 5 ft.
And the max height it reaches is 21 ft.....but it needs to reach a height of 25ft....so, no, it won't be thrown high enough to reach the ledge....
Here's a graph that substitutes y for h and x for t....
https://www.desmos.com/calculator/pzsjsonnv0