you deposit 10,000 in an account that pays 8.5% annual interest compounded monthly. what is the balance after 8 years? growth and decay func

OK...we have this

A_n = A₀ (1 + r/n) ^nt

Where

A_n = the amount accumulated at the end of the period

A₀ = the amount invested ($10000)

r= the interest rate (8.5% = .085)

n = the number of compoundings per year (12)

t = the time in years (8)

So we have

A_n = 10000(1  + .085/12)^(12*8)  = 

$${\mathtt{10\,000}}{\mathtt{\,\times\,}}{\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{0.085}}}{{\mathtt{12}}}}\right)}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{8}}\right)} = {\mathtt{19\,691.519\: \!725\: \!320\: \!224\: \!411\: \!3}}$$

≈ $19,691.52