You drop a stone down a well that is 9.5 m deep. How long is it before you hear the splash? The speed of sound in air is 343 m/s and air resistance is negligible.
We need to calculate the time for the stone to fall...we have
-9.5 = -4.9t^2 divide both sides by -4.9
1.94 = t^2 take the square root of each side
t = 1.39 secs.
Since sound travels at 343m/s...the time for the sound to travel back up the well = 9.5m / 343m/s = about 0.028 sec.
So the splash is heard [1.39 + 0.028 ] = about 1.418 seconds after the stone is dropped
We need to calculate the time for the stone to fall...we have
-9.5 = -4.9t^2 divide both sides by -4.9
1.94 = t^2 take the square root of each side
t = 1.39 secs.
Since sound travels at 343m/s...the time for the sound to travel back up the well = 9.5m / 343m/s = about 0.028 sec.
So the splash is heard [1.39 + 0.028 ] = about 1.418 seconds after the stone is dropped