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You start at 10000, each year your car loses 10% of its value but at the end of each year you add $100. Let C(n) be the value of your car after n years(so C(0) = 10000). Write a recurrence relation for C(n)? HELP PLEASE

 Dec 5, 2014

Best Answer 

 #1
avatar+118723 
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c(0)=10000

C(1)=0.9*C(0)+100*1

C(n)=0.9*C(n-1)+100n

 

I think that is what you want.    

 Dec 5, 2014
 #1
avatar+118723 
+5
Best Answer

c(0)=10000

C(1)=0.9*C(0)+100*1

C(n)=0.9*C(n-1)+100n

 

I think that is what you want.    

Melody Dec 5, 2014

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