Y - 3 = 3(x + 1)
I need to know
1. The slope of the line
2. What point the line passes through, which is the basis of this equation
3. Rewritten in slope intercept form.
4. the Y intercept of the line.
5. Rewritten in standard form.
6.The X intercept of the line.
Honestly if you could that would be great this is kinda clutch on my homework right now. I want to blame my teacher but I guess it's my fault for being stupid not his fualt for not giving 2 shits about my education
IF YOU CAN SEND ME A LINK TO A SITE THAT COULD YOU KNOW... TEACH ME THIS STUFF.
I would love to learn how I just can't find a site to help me you know... learn
+11 For help, khan academy is just the place.
First convert to slope-intercept form:
y=mx+b
m=slope
b=y-intercept
Y-3=3(x+1)
y-3=3x+3
+3 +3
y=3x+6
1. m=3
2. (-1,3):
Point slope form (the form the equation was in):
y-y1=m(x-x1)
y-(3)=3(x-(-1))
x1=-1
y1=3
(-1,3)
3. y=3x+6, figured that out abovve
4. b=6
5.3x-y=-6:
y=3x+6
-6-y -6-y
-6=3x-y
6.-2
Graph it. It's pretty simple. If you can't, the formula is:
-(b/m) (Actually, I don't know if there is a formula, but this will still work.)
b=6
m=3
-(6/3)=-2
If you took the time to read all of that, you should have at least a basic understanding of your homework.
+11 For help, khan academy is just the place.
First convert to slope-intercept form:
y=mx+b
m=slope
b=y-intercept
Y-3=3(x+1)
y-3=3x+3
+3 +3
y=3x+6
1. m=3
2. (-1,3):
Point slope form (the form the equation was in):
y-y1=m(x-x1)
y-(3)=3(x-(-1))
x1=-1
y1=3
(-1,3)
3. y=3x+6, figured that out abovve
4. b=6
5.3x-y=-6:
y=3x+6
-6-y -6-y
-6=3x-y
6.-2
Graph it. It's pretty simple. If you can't, the formula is:
-(b/m) (Actually, I don't know if there is a formula, but this will still work.)
b=6
m=3
-(6/3)=-2
If you took the time to read all of that, you should have at least a basic understanding of your homework.
