\(\)Given that \(x+x^2+x^3+x^4 = 5\), what is the value of \(\frac{1-x^5}{1-x}\)
x^4 + x^3 + x^2 + x + 1
1-x [ -x^5 + 0x^4 + 0x^3 + 0x^2 + 0x + 1 ]
- x^5 + x^4
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- x^4 + 0x^3
- x^4 + x^3
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- x^3 + 0x^2
- x^3 + x^2
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- x^2 + 0x
- x^2 + x
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- x + 1
- x + 1
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Notice that ( x^4 + x^3 + x^2 + x) + 1 = 5 + 1 = 6