Z.1) Find the linear equation represented by the points in the given tables, given those point in order to draw the gragh of the equation. (4,2) (6,4) (7,5)
Notice the last two points........"x" and "y" change by 1 from (6,4) to (7,5)...And the "slope" is defined by (change in y) /(change in x) = (1 / 1) = 1
So using the slope and one of the points ....we'll use ( 4, 2)....we can use the point-slope formula to write the equation..we have....
y - y1 = m(x - x1) where x1 = 4, y1 = 2 and the slope, "m" = 1....so we have...
y - 2 = 1 (x - 4)
y - 2 = x - 4 add 2 to both sides
y = x - 2
Check to see that the other two points "work" in this equation !!!
Notice the last two points........"x" and "y" change by 1 from (6,4) to (7,5)...And the "slope" is defined by (change in y) /(change in x) = (1 / 1) = 1
So using the slope and one of the points ....we'll use ( 4, 2)....we can use the point-slope formula to write the equation..we have....
y - y1 = m(x - x1) where x1 = 4, y1 = 2 and the slope, "m" = 1....so we have...
y - 2 = 1 (x - 4)
y - 2 = x - 4 add 2 to both sides
y = x - 2
Check to see that the other two points "work" in this equation !!!