z^6+2z^5+2z^4+2z^3+2z^2+2z+1=0, solve for Z in Complex numbers(z=a+bi,i^2=-1)

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z^6+2*z^5+2*z^4+2*z^3+2*z^2+2*z+1=0, solve for Z in Complex numbers(z=a+b*i,i^2=-1)

Guest Apr 6, 2016

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Z=0

Guest · Answer 1 · 2016-04-06T01:27:44

By factorizing it becomes: (z^4+z^2+1)*(z+1)^2=0

z^6+2*z^5+2*z^4+2*z^3+2*z^2+2*z+1=0, solve for Z in Complex numbers(z=a+b*i,i^2=-1)