+0  
 
0
145
1
avatar

z is directly proportional to the square of x and inversely proportional to the square root of y. If z=12 when x=2 and y=4, find z when x=6 and y=32

 

any help is greatly appreciated!

Guest Jun 3, 2017
Sort: 

1+0 Answers

 #1
avatar+26265 
+1

We have  \(z=k\frac{x^2}{\sqrt{y}}\)   where k is a constant

 

Find k as  \(k=12\frac{\sqrt{4}}{2^2}\rightarrow6\)

 

So when x = 6 and y = 32 we have \(z=6\frac{6^2}{\sqrt{32}}\rightarrow27\sqrt2\)

.

Alan  Jun 3, 2017

24 Online Users

avatar
avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details