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what are the 0 functions of x^2-5x+3

 Feb 20, 2016
 #1
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+5

Solve for x:
x^2-5 x+3 = 0

Subtract 3 from both sides:
x^2-5 x = -3

Add 25/4 to both sides:
x^2-5 x+25/4 = 13/4

Write the left hand side as a square:
(x-5/2)^2 = 13/4

Take the square root of both sides:
x-5/2 = sqrt(13)/2 or x-5/2 = -sqrt(13)/2

Add 5/2 to both sides:
x = 5/2+sqrt(13)/2 or x-5/2 = -sqrt(13)/2

Add 5/2 to both sides:
Answer: |  x = 5/2+sqrt(13)/2          or           x = 5/2-sqrt(13)/2

 Feb 20, 2016

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