civonamzuk

Agreed!  This is one of those questions that makes you ask yourself: what did a poet want to say...?

tan-1 70 over 10

70/10=7

tan^-1 (7) = 81.87^o

what is 75 percent of 405

@rosala:/ Your answer is only 50%  correct!

A 100% correct  answer is:>       75%  of  405  is  303.75  

size of angle x when the opp is 4.5 ad adj is 11?

tan(x) = 4.5/11

x = 22.25^o

@DarkBlaze:/   The question asks for the length of the arc of the 250^o  sector, not the area of it.

A circle has a radius of 32cm. To the nearest hundredth, what is the length of the arc that has a measure of 250 degrees(?)

2(32*pi) = 201.06

201.06/360=0.5585

0.5585*250=139.63

how do you find square roots?

Here's a link:>

http://www.homeschoolmath.net/teaching/square-root-algorithm.php

The guy who inherited a center piece of the land, must be in a good relationship with, at least, one of his brothers.

Heureka's answer is correct!

The dotted diagonal AC (Fig. 42)  has the length of twice the radius. Find the area of the emblem only.

Radius (r) = 1 

AC = 2r       r = 1

Area of the square is:  (sqrt(2))²  = 2.000u²

Triangles:  (lkC + oAf) = (sqrt(2) -1)² = 0.171572875253809862u²

Half circle area is:  r²pi/2 = 1.5707963267948966u²

(2.000u² - 1.570796326794896u² - 0.17157287525380986u²)*2= 0.515261595902587u²