civonamzuk

2x + 2 = 10

x = 4

UZ = VZ = 7.5

WU = 5

Arc QWR ≈ 106.26º

WZ = YZ = 12.5

Area = 12.52pi

Circumference = 25pi

DB = 12(12 / 16)

BD = 20(20 / 16) 

x = 12 / (8/12) - 8

D is the centroid of △ABC. What is the value of x when BD = 45 - x and BF = 21x?

(I assume that BF is a median of triangle ABC)

BD : DF = 2 : 1

45 - x = 2(21x)

x = 45/43

1. Three segments have a total length of 26 inches. The first segment is 2 less than three times the second segment. The third segment is 1 more than five times the second segment. What are the lengths of the three segments? 

All three variables must be defined in terms of x.

1st      3x - 2

2nd     x

3rd      5x + 1

3x - 2 + x + 5x + 1 = 26

9x = 27

x = 3

18 / 30 = x / 24              or                 x = (24 * 18) / 30

30x = 24 * 18                                     x = 432 / 30

x = 14.4                                             x = 14.4

@fiora:/  Melody's answered  both questions of yours.

1st answer:     The length of  PM could be either  1  or  3 ;

2nd answer:    IF a point N is on a line segment PQ,  the angle NOP is 30^o , and the length of PM is 1, THEN the angle POM = 18.435^o , and the area of a triangle NOM = 0.464u² !

Bravo, Melody! 

The angle NOP is NOT 30^o ; but if it is, then a point N is in between M and P.

∠OMP = 63.435^o ,      ∠MOP = 71.565^o ,    PM = 3

    @heureka:/