dierdurst

\(23.4*2.20 = 51.48\). This means that there was \(51.48\) kg of chowders eaten in \(6\) minutes. \(51.48\) kg = \(51480\) g. There are \(3600\) seconds in \(6\) minutes. Our fraction is \(\frac{​​​​51480}{3600} = \frac{1287}{90} = \frac{143}{10}\) chowder eaten in grams per second.

- Daisy

The GCF for \(30, 24,\) and \(12\) is \(6\). This means that there will be \(6\) tanks. (Correct me if I'm wrong, I'm not so sure about this one. I may have read it wrong).

- Daisy

You cannot simplify a negative number, because no two same numbers with any positivity have a product that is negative. \(\sqrt{-64} = 8i\). \(i\) stands for an imaginary number. 

- Daisy

In order to find the probability of a certain event, we need to set up the fraction; \(\frac{p(successful)}{p(possible)}\). Let's see how many numbers are successful:

Less than or equal to 5: \(1, 2, 3, 4, 5\)

Multiple of 7: \(7, 14, 21, 28\).

These nine numbers are successful, so your probability would be \(\frac{9}{30} = \frac{3}{10}\).

- Daisy

Problem 1: \(3600\) seconds are in \(1\) hour, so we can do \(\frac{4508}{3600} ≈ 1.25\) hours. 

Problem 2: \(258\) nanometers is equal to \(2.579999999e-9\) hectometers, which is about \(2.58e-9\) hectometers.

Problem 3: In order to convert micrograms to miligrams, we have to move to decimal point \(3\) times to the left. This gives us \(0.0081\) miligrams.

Problem 4: Remember: K H D B D C M(Kilo, Hecto, Deca, Basic, Deci, Centi, and Mili). This tells us that in order to convert kiloliters to centiliters, we need to move the decimal point \(5\) times to the right. This gives us \(640000\) centiliters. 

Problem 5: To convert kilograms to grams, we have to move the decimal point \(3\) times to the right. This will give us \(83000\) grams. 

- Daisy

I don't really see much to explain here, aside from the fact that the horizontal axis would be the model of the car and the vertical axis would be the average miles per gallon of gas. Therefore, your answer would be B. model of car.

- Daisy

We can check each country:

Australia; From 1950 - 2000, there is an increase, and from 2000 - 2050 there is also an increase. So this country will expect an increase in population.

Hungary; While there is a slight increase from 1950 - 2000, there is also a slight decrease from 2000 - 2050.

Canada; From 1950 - 2000, there is an increase, and from 2000 - 2050 there is also an increase. So this country will expect an increase in population.

S. Korea; From 1950 - 2000, there is an increase, but there is a decrease from 2000 - 2050.

Egypt; From 1950 - 2000, there is an increase, and from 2000 - 2050 there is also an increase. So this country will expect an increase in population.

Out of these 5 countries, 3(Australia, Canada, and Egypt) will expect an increase in population from 1905 to 2000 and from 2000 to 2050. 

- Daisy 

This quadratic, \(z^2 - z - 3 = 0\) is a bit trickier. For this one, we need to use the quadratic formula, which is \(\frac{-b ± \sqrt{b^2 - 4ac}}{2a}\).

When we plug in the values of \(a, b,\) and \(c\), we get \(\frac{-(-1) ± \sqrt{(-1)^2 - 4(1)(-3)}}{2(1)} = \frac{1±\sqrt{13}}{2}\). This means \(z = \frac{1}{2} + \frac{1}{2}\sqrt{13}\) or \(z = \frac{1}{2} + \frac{-1}{2}\sqrt{13}\).

- Daisy

\(2x^2 + 5x + 3 = 0\) factors to \((2x+3)(x+1) = 0\).

This means that \(x = \frac{-3}{2}\) and \(x = -1\). 

- Daisy

By this graph, we can pick two points to find the slope. Two clear points are \((0, 3)\) and \((1, 5)\). Slope = \(\frac{rise}{run}\). The rise is \(2\) and the run is \(1.\) Therefore, the slope is \(\frac{2}{1} = 2\), or \(D\).

- Daisy