gibsonj338

\(\frac{44!}{(44-4)!}\times4!\)

\(\frac{44!}{40!}\times4!\)

\(\frac{1\times2\times3\times4\times5\times6\times7\times8\times9\times10\times11\times12\times13\times14\times15\times16\times17\times18\times19\times20\times21\times22\times23\times24\times25\times26\times27\times28\times29\times31\times31\times32\times33\times34\times35\times36\times37\times38\times39\times40\times41\times42\times43\times44}{1\times2\times3\times4\times5\times6\times7\times8\times9\times10\times11\times12\times13\times14\times15\times16\times17\times18\times19\times20\times21\times22\times23\times24\times25\times26\times27\times28\times29\times30\times31\times32\times33\times34\times35\times36\times3\times38\times39\times40}\times1\times2\times3\times4\)

\(\frac{2658271574788448768043625811014615890319638528000000000}{1\times2\times3\times4\times5\times6\times7\times8\times9\times10\times11\times12\times13\times14\times15\times16\times17\times18\times19\times20\times21\times22\times23\times24\times25\times26\times27\times28\times29\times30\times31\times32\times33\times34\times35\times36\times3\times38\times39\times40}\times1\times2\times3\times4\)

\(\frac{2658271574788448768043625811014615890319638528000000000}{815915283247897734345611269596115894272000000000}\times1\times2\times3\times4\)

\(\frac{2658271574788448768043625811014615890319638528000000000}{815915283247897734345611269596115894272000000000}\times24\)

\(3258024\times24\)

\(78192576\)

\(\sqrt{47}\)

Exact answer

\(\sqrt{47}\)

Approximate answer

\(6.8556546004010441...\)

\(7.72\)

\(7\frac{72}{100}\)

\(7+\frac{72}{100}\)

\(7+\frac{18}{25}\)

\(\frac{175}{25}+\frac{18}{25}\)

\(\frac{193}{25}\)

\({3}^{-1}\)

\(\frac{1}{{3}^{1}}\)

\(\frac{1}{3}\)

\(0.33333333333...\)

Two ways to solve this expression

Way One:

\(\frac{\frac{2}{8}}{\frac{9}{18}}\)

\(\frac{2}{8}\times\frac{18}{9}\)

\(\frac{36}{72}\)

\(\frac{1}{2}\)

\(0.5\)

Way Two:

\(\frac{\frac{2}{8}}{\frac{9}{18}}\)

\(\frac{2}{8}\times\frac{18}{9}\)

\(\frac{1}{4}\times2\)

\(\frac{2}{4}\)

\(\frac{1}{2}\)

\(0.5\)

I get you now.  I did not see the "-" in front of the log.

How did you get \({5}^{-1}\)?

I took a trignometry class at Portland Community College in Portland, Oregon last year in September and my math book says that the genral formula for the area of a triangle is \(K=\frac{1}{2}bh\) where \(K=area;\) \(b=base;\) \(h=height\).  If you know the lengths of two sides and an angle but do not know the base or the height, you can use the formula \(K=\frac{1}{2}ab\times sin(C)\)where \(K=area;\) a = side a; b = side b; C = angle C.  You can also use the formula\(K=\frac{1}{2}bc\times sin(A)\)where \(K=area;\) b = side b; c = side c; A = angle A.  You can also use the formula \(K=\frac{1}{2}ac\times sin(B)\)where \(K=area;\) a = side a; c = side c; B = angle B.  If you know the lengths of all three sides but do not know any of the angles, the base or the height, you can use the formula \(K=\sqrt{s\times(s-a)\times(s-b)\times(s-c)}\)where \(s=\frac{1}{2}\times(a+b+c);\)a = side a; b = side b; c = side c.

\(2\times{(-3)}^{3}+4\times{(-3)}^{2}\)

\(2\times-27+4\times{(-3)}^{2}\)

\(2\times-27+4\times9\)

\(-54+4\times9\)

\(-54+36\)

\(-18\)

Peas - $0.99/lb or Peas - $4.59/5lbs

Take $4.59 and divide it by 5 to get the price per pound.

$4.59/5 = $0.918

91.8¢/lb vs. 99¢/lb.  Which is the better deal?