Write the equation for a line that goes through points (-4, -1) and (0, 3).
\(y=mx+b;\) \(y = y-value;\) \(m = slope;\) \(x=x-value;\) \(b = y-intersept\)
First, find the slope. To find the slope use the equation m = ∆y/∆x (m=(y2-y1)(/x2-x1)). You can let the first point the starting point and the second point the ending point or let the second point be the starting point and the second point be the ending point. I will let the first point be the starting point and let the second point be the ending point.
\(m=\frac{-1-3}{-4-0}\)
\(m=\frac{-4}{-4-0}\)
\(m=\frac{-4}{-4}\)
\(m=1\)
\(y=1x+b\)
\(y=x+b\)
To find the value for b, take one of the points and subsitiute for y and x. I will use the first point.
\(-1=-4+b\)
\(3=b\)
\(b=3\)
The equation
\(y=x+3\)
Clink on the following link to see a graph of this equation: https://www.desmos.com/calculator/8wgsctwraw
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