gibsonj338

Actually, one year does not equal 365 days but instead equals 365.25 days.

\({2}^{2}x+256+\frac{1}{2}\)

\(4x+256+\frac{1}{2}\)

\(4x+\frac{512}{2}+\frac{1}{2}\)

\(4x+\frac{513}{2}\)

\(4x+256.5\)

                                \(5.8468±1.96\times\frac{0.75241}{\sqrt{20}}\)

\(5.8468+1.96\times\frac{0.75241}{\sqrt{20}}\)               \(5.8468-1.96\times\frac{0.75241}{\sqrt{20}}\)

\(5.8468+1.96\times\frac{0.75241}{\sqrt{4\times5}}\)               \(5.8468-1.96\times\frac{0.75241}{\sqrt{4\times5}}\)

\(5.8468+1.96\times\frac{0.75241}{\sqrt{4}\times\sqrt{5}}\)               \(5.8468-1.96\times\frac{0.75241}{\sqrt{4}\times\sqrt{5}}\)

\(5.8468+1.96\times\frac{0.75241}{2\sqrt{5}}\)               \(5.8468-1.96\times\frac{0.75241}{2\sqrt{5}}\)

\(5.8468+\frac{1.4747236}{2\sqrt{5}}\)                            \(5.8468-\frac{1.4747236}{2\sqrt{5}}\)

\(\frac{11.6936\sqrt{5}}{2\sqrt{5}}+\frac{1.4747236}{2\sqrt{5}}\)                          \(\frac{11.6936\sqrt{5}}{2\sqrt{5}}-\frac{1.4747236}{2\sqrt{5}}\)

\(\frac{11.6936\sqrt{5}+1.4747236}{2\sqrt{5}}\)                                 \(\frac{11.6936\sqrt{5}-1.4747236}{2\sqrt{5}}\)

\(\frac{11.6936\sqrt{5}+1.4747236}{2\sqrt{5}}\times\frac{\sqrt{5}}{\sqrt{5}}\)                      \(\frac{11.6936\sqrt{5}-1.4747236}{2\sqrt{5}}\times\frac{\sqrt{5}}{\sqrt{5}}\)

\(\frac{\sqrt{5}(11.6936\sqrt{5}+1.4747236}{2\times5}\)                           \(\frac{\sqrt{5}(11.6936\sqrt{5}-1.4747236}{2\times5}\)

\(\frac{11.6936\times5+1.4747236\sqrt{5}}{2\times5}\)                               \(\frac{11.6936\times5-1.4747236\sqrt{5}}{2\times5}\)

\(\frac{58.468+1.4747236\sqrt{5}}{2\times5}\)                                     \(\frac{58.468-1.4747236\sqrt{5}}{2\times5}\)

\(\frac{58.468+1.4747236\sqrt{5}}{10}\)                                      \(\frac{58.468-1.4747236\sqrt{5}}{10}\)

\(\frac{58.468}{10}+\frac{1.4747236\sqrt{5}}{10}\)                                   \(\frac{58.468}{10}-\frac{1.4747236\sqrt{5}}{10}\)

\(5.8468+\frac{1.4747236\sqrt{5}}{10}\)                                   \(5.8468-\frac{1.4747236\sqrt{5}}{10}\)

\(6.1765582217623209\)                              \(5.5170417782376791\)

\(\sqrt{-121}\)

\(\sqrt{121}\times\sqrt{-1}\)

\(11\sqrt{-1}\)

\(11i\)

\(y4=-8\)

\(\frac{y4}{4}=\frac{8}{4}\)

\(y1=\frac{8}{4}\)

\(y=\frac{8}{4}\)

\(y=2\)

The problem said to be in feet not yards.  16 is yards.  To convert into feet multiply 16 by 3 to get 48 feet.

\(x≥-\frac{1}{2}±\frac{\sqrt{11}}{2}i\)

\(\frac{{x}^{2}+x+3}{{2x}^{2}+x-6}≥0\)

\(\frac{{x}^{2}+x+3}{{2x}^{2}+x-6}\times({2x}^{2}+x-6)≥0\times({2x}^{2}+x-6)\)

\(\frac{({x}^{2}+x+3)({2x}^{2}+x-6)}{{2x}^{2}+x-6}≥0\times({2x}^{2}+x-6)\)

\({x}^{2}+x+3≥0\times({2x}^{2}+x-6)\)

\({x}^{2}+x+3≥0\)

\(x ≥ {-1 \pm \sqrt{1^2-4(1)(3)} \over 2(1)}\)

\(x ≥ {-1 \pm \sqrt{1-4(1)(3)} \over 2(1)}\)

\(x ≥ {-1 \pm \sqrt{1-4(3)} \over 2(1)}\)

\(x ≥ {-1 \pm \sqrt{1-12} \over 2(1)}\)

\(x ≥ {-1 \pm \sqrt{-11} \over 2(1)}\)

\(x ≥ {-1 \pm \sqrt{11}i \over 2(1)}\)

\(x ≥ {-1 \pm \sqrt{11}i \over 2}\)

Wouldn't the answer be \(±5i\), not \(±\sqrt{5}i\)?

\(2y+3=\frac{-1}{3}\times(x-2)\)

\(2y+3=-\frac{1}{3}\times(x-2)\)

\(3(2y+3)=3(-\frac{1}{3}\times(x-2))\)

\(6y+9=3(-\frac{1}{3}\times(x-2))\)

\(6y+9=-1(x-2)\)

\(6y+9=-(x-2)\)

\(6y+9=-x+2\)

\(6y+9-9=-x+2-9\)

\(6y+0=-x+2-9\)

\(6y=-x+2-9\)

\(6y=-x-7\)

\(6y+x=-x-7+x\)

\(6y+x=-7+0\)

\(6y+x=-7\)

\(x+6y=-7\)