gibsonj338

Actually, one year does not equal 365 days but instead equals 365.25 days.

${2}^{2}x+256+\frac{1}{2}$

$4x+256+\frac{1}{2}$

$4x+\frac{512}{2}+\frac{1}{2}$

$4x+\frac{513}{2}$

$4x+256.5$

                                $5.8468±1.96\times\frac{0.75241}{\sqrt{20}}$

$5.8468+1.96\times\frac{0.75241}{\sqrt{20}}$               $5.8468-1.96\times\frac{0.75241}{\sqrt{20}}$

$5.8468+1.96\times\frac{0.75241}{\sqrt{4\times5}}$               $5.8468-1.96\times\frac{0.75241}{\sqrt{4\times5}}$

$5.8468+1.96\times\frac{0.75241}{\sqrt{4}\times\sqrt{5}}$               $5.8468-1.96\times\frac{0.75241}{\sqrt{4}\times\sqrt{5}}$

$5.8468+1.96\times\frac{0.75241}{2\sqrt{5}}$               $5.8468-1.96\times\frac{0.75241}{2\sqrt{5}}$

$5.8468+\frac{1.4747236}{2\sqrt{5}}$                            $5.8468-\frac{1.4747236}{2\sqrt{5}}$

$\frac{11.6936\sqrt{5}}{2\sqrt{5}}+\frac{1.4747236}{2\sqrt{5}}$                          $\frac{11.6936\sqrt{5}}{2\sqrt{5}}-\frac{1.4747236}{2\sqrt{5}}$

$\frac{11.6936\sqrt{5}+1.4747236}{2\sqrt{5}}$                                 $\frac{11.6936\sqrt{5}-1.4747236}{2\sqrt{5}}$

$\frac{11.6936\sqrt{5}+1.4747236}{2\sqrt{5}}\times\frac{\sqrt{5}}{\sqrt{5}}$                      $\frac{11.6936\sqrt{5}-1.4747236}{2\sqrt{5}}\times\frac{\sqrt{5}}{\sqrt{5}}$

$\frac{\sqrt{5}(11.6936\sqrt{5}+1.4747236}{2\times5}$                           $\frac{\sqrt{5}(11.6936\sqrt{5}-1.4747236}{2\times5}$

$\frac{11.6936\times5+1.4747236\sqrt{5}}{2\times5}$                               $\frac{11.6936\times5-1.4747236\sqrt{5}}{2\times5}$

$\frac{58.468+1.4747236\sqrt{5}}{2\times5}$                                     $\frac{58.468-1.4747236\sqrt{5}}{2\times5}$

$\frac{58.468+1.4747236\sqrt{5}}{10}$                                      $\frac{58.468-1.4747236\sqrt{5}}{10}$

$\frac{58.468}{10}+\frac{1.4747236\sqrt{5}}{10}$                                   $\frac{58.468}{10}-\frac{1.4747236\sqrt{5}}{10}$

$5.8468+\frac{1.4747236\sqrt{5}}{10}$                                   $5.8468-\frac{1.4747236\sqrt{5}}{10}$

$6.1765582217623209$                              $5.5170417782376791$

$\sqrt{-121}$

$\sqrt{121}\times\sqrt{-1}$

$11\sqrt{-1}$

$11i$

$y4=-8$

$\frac{y4}{4}=\frac{8}{4}$

$y1=\frac{8}{4}$

$y=\frac{8}{4}$

$y=2$

The problem said to be in feet not yards.  16 is yards.  To convert into feet multiply 16 by 3 to get 48 feet.

$x≥-\frac{1}{2}±\frac{\sqrt{11}}{2}i$

$\frac{{x}^{2}+x+3}{{2x}^{2}+x-6}≥0$

$\frac{{x}^{2}+x+3}{{2x}^{2}+x-6}\times({2x}^{2}+x-6)≥0\times({2x}^{2}+x-6)$

$\frac{({x}^{2}+x+3)({2x}^{2}+x-6)}{{2x}^{2}+x-6}≥0\times({2x}^{2}+x-6)$

${x}^{2}+x+3≥0\times({2x}^{2}+x-6)$

${x}^{2}+x+3≥0$

$x ≥ {-1 \pm \sqrt{1^2-4(1)(3)} \over 2(1)}$

$x ≥ {-1 \pm \sqrt{1-4(1)(3)} \over 2(1)}$

$x ≥ {-1 \pm \sqrt{1-4(3)} \over 2(1)}$

$x ≥ {-1 \pm \sqrt{1-12} \over 2(1)}$

$x ≥ {-1 \pm \sqrt{-11} \over 2(1)}$

$x ≥ {-1 \pm \sqrt{11}i \over 2(1)}$

$x ≥ {-1 \pm \sqrt{11}i \over 2}$

Wouldn't the answer be $±5i$, not $±\sqrt{5}i$?

$2y+3=\frac{-1}{3}\times(x-2)$

$2y+3=-\frac{1}{3}\times(x-2)$

$3(2y+3)=3(-\frac{1}{3}\times(x-2))$

$6y+9=3(-\frac{1}{3}\times(x-2))$

$6y+9=-1(x-2)$

$6y+9=-(x-2)$

$6y+9=-x+2$

$6y+9-9=-x+2-9$

$6y+0=-x+2-9$

$6y=-x+2-9$

$6y=-x-7$

$6y+x=-x-7+x$

$6y+x=-7+0$

$6y+x=-7$

$x+6y=-7$