gibsonj338

$W=2$,  $I=5$,  $N=8$,  $E=6$

$3\times862=2586$

This took me several hours to figure this out as there were 1001 possibilities.  Thanks to Microsoft Excel, I was able to get to the answer.

To prove that ${2}^{0}=1$, look at this example

$\frac{{2}^{5}}{{2}^{5}}$

$\frac{32}{{2}^{5}}$

$\frac{32}{32}$

$1$

$\frac{{2}^{5}}{{2}^{5}}$

${2}^{5-5}$

${2}^{0}$

$1$

Actually anything with an exponent of 0 except for 0 is not 0 but is 1.

${0}^{0}≠0$

${0}^{0}$ is $Undefined$ because you cannot take $0$ and raise it to the $0$ power.  If you take any integer except for $0$ and raise it to the power of $0$, you get $1$.

${0}^{0}$

$Undefined$

To find the diameter of the circle with only the area known, use the formula $A=\pi\times{r}^{2}$ where $A=Area$, $\pi≈3.1415926535897932$, $r=radius$.  We know that Area is equal to ${56.75in}^{2}$and we know that $\pi≈3.1415926535897932$, but we do not know what the radius is equal to.  In order to figure out what the radius is equal to, solve for r and then plug in what we know.

$A=\pi\times{r}^{2}$

$\frac{A}{\pi}=\frac{\pi\times{r}^{2}}{\pi}$

$\frac{A}{\pi}=1\times{r}^{2}$

$\frac{A}{\pi}={r}^{2}$

$\sqrt{\frac{A}{\pi}}=\sqrt{{r}^{2}}$

$\sqrt{\frac{A}{\pi}}=r$

$r=\sqrt{\frac{A}{\pi}}$

$r=\frac{\sqrt{A}}{\sqrt{\pi}}$

$r=\frac{\sqrt{A}}{\sqrt{\pi}}\times\frac{\sqrt{\pi}}{\sqrt{\pi}}$

$r=\frac{\sqrt{A}\sqrt{\pi}}{\sqrt{\pi}\sqrt{\pi}}$

$r=\frac{\sqrt{A\pi}}{\sqrt{\pi}\sqrt{\pi}}$

$r=\frac{\sqrt{A\pi}}{\sqrt{\pi\pi}}$

$r=\frac{\sqrt{A\pi}}{\sqrt{{\pi}^{2}}}$

$r=\frac{\sqrt{A\pi}}{\pi}$

$r=\frac{\sqrt{56.75\pi}}{\pi}$

$r≈\frac{\sqrt{56.75\times3.1415926535897932}}{3.1415926535897932}$

$r≈\frac{\sqrt{178.2853830912207641}}{3.1415926535897932}$

$r≈\frac{13.3523549642458488717}{3.1415926535897932}$

$r≈4.2501865889546685678486$

Now we know that the radius is approximately equal to $4.2501865889546685678486$; however, we want to know what the diamanter of the circle is, not the radius.  In order to find the diamater, use the formula $d=2r$ where $d=diamater$, $r=radius$.

$d=2r$

$d≈2\times4.2501865889546685678486$

$d≈8.5003731779093371356972$

The diameter of a circle wth an area of ${56.75in}^{2}$ is approximately equal to $8.5003731779093371356972$.

If you mean $({\frac{1}{3})}^{11}$

$({\frac{1}{3})}^{11}$

$\frac{{1}^{11}}{{3}^{11}}$

$\frac{1\times1\times1\times1\times1\times1\times1\times1\times1\times1\times1}{{}^{{3}^{11}}}$

$\frac{1\times1\times1\times1\times1\times1\times1\times1\times1\times1}{{}^{{3}^{11}}}$

$\frac{1\times1\times1\times1\times1\times1\times1\times1\times1}{{}^{{3}^{11}}}$

$\frac{1\times1\times1\times1\times1\times1\times1\times1}{{}^{{3}^{11}}}$

$\frac{1\times1\times1\times1\times1\times1\times1}{{}^{{3}^{11}}}$

$\frac{1\times1\times1\times1\times1\times1}{{}^{{3}^{11}}}$

$\frac{1\times1\times1\times1\times1}{{}^{{3}^{11}}}$

$\frac{1\times1\times1\times1}{{}^{{3}^{11}}}$

$\frac{1\times1\times1}{{}^{{3}^{11}}}$

$\frac{1\times1}{{}^{{3}^{11}}}$

$\frac{1}{{}^{{3}^{11}}}$

$\frac{1}{3\times3\times3\times3\times3\times3\times3\times3\times3\times3\times3}$

$\frac{1}{9\times3\times3\times3\times3\times3\times3\times3\times3\times3}$

$\frac{1}{27\times3\times3\times3\times3\times3\times3\times3\times3}$

$\frac{1}{81\times3\times3\times3\times3\times3\times3\times3}$

$\frac{1}{243\times3\times3\times3\times3\times3\times3}$

$\frac{1}{729\times3\times3\times3\times3\times3}$

$\frac{1}{2187\times3\times3\times3\times3}$

$\frac{1}{6561\times3\times3\times3}$

$\frac{1}{19683\times3\times3}$

$\frac{1}{59049\times3}$

$\frac{1}{177147}$

$0.0000056450292695$

If you mean $\frac{1}{{3}^{11}}$

$\frac{1}{3\times3\times3\times3\times3\times3\times3\times3\times3\times3\times3}$

$\frac{1}{9\times3\times3\times3\times3\times3\times3\times3\times3\times3}$

$\frac{1}{27\times3\times3\times3\times3\times3\times3\times3\times3}$

$\frac{1}{81\times3\times3\times3\times3\times3\times3\times3}$

$\frac{1}{243\times3\times3\times3\times3\times3\times3}$

$\frac{1}{729\times3\times3\times3\times3\times3}$

$\frac{1}{2187\times3\times3\times3\times3}$

$\frac{1}{6561\times3\times3\times3}$

$\frac{1}{19683\times3\times3}$

$\frac{1}{59049\times3}$

$\frac{1}{177147}$

$0.0000056450292695$

$\frac{1}{3}\times\frac{1}{9}$

$\frac{1}{27}$

$0.037037037037037...$

$4+\frac{2}{3}x=9+\frac{1}{2}x$

$[4+\frac{2}{3}x]\times6=[9+\frac{1}{2}x]\times6$

$24+\frac{12}{3}x=[9+\frac{1}{2}x]\times6$

$24+4x=[9+\frac{1}{2}x]\times6$

$24+4x=54+\frac{6}{2}x$

$24+4x=54+3x$

$24+4x-3x=54+3x-3x$

$24+1x=54+3x-3x$

$24+x=54+3x-3x$

$24+x=54+0x$

$24+x=54+0$

$24+x=54$

$24+x-24=54-24$

$x-0=54-24$

$x=54-24$

$x=30$

To find the x intercept, subsitute 0 for x and slove for y:

$3x+9y=9$

$3(0)+9y=9$

$0+9y=9$

$9y=9$

$\frac{9y}{9}=\frac{9}{9}$

$1y=\frac{9}{9}$

$y=\frac{9}{9}$

$y=1$

x intersept: (0, 1)

To find the y intercept, subsitute 0 for y and slove for x:

$3x+9y=9$

$3x+9(0)=9$

$3x+0=9$

$3x=9$

$\frac{3x}{3}=\frac{9}{3}$

$1x=\frac{9}{3}$

$x=\frac{9}{3}$

$x=3$

y intersept: (3,0)

You can also find the x and y intersepts by graphing the equation by subsiting numbers for x and getting aswers for y or subsititing numbers for y and getting answers for x and then plot the points and then connect the points.  Click on the following link to see the graph of this equation.