+285 Here there are two way to do it in the link https://web2.0calc.com/questions/maths_68552 but they got 40
Here is one way by TheXSquaredFactor:
Let's consider properties of integers that fit the following conditions.
Even three-digit number
Less than 500
Comprised of the digits 1 to 5
It is probably easiest to consider the possibilities for the final digit first. Because one criterion is an even number, the final digit must be either a 2 or a 4.
Eliminating possibilities for the first digit is relatively simple, as well. The numbers must not exceed 500, so the first digit of this three-digit integer cannot be a 5 because it would violate the aforementioned criterion. Otherwise, though, no restriction exists for the beginning digit, so the numbers 1 to 4 are all candidates for the first digit
Excluding the digit restriction, the middle digit cannot affect the ability for a number to qualify for any of the predetermined conditions. Therefore, 1 to 5 are all possibilities.
There are 4 possibilities for the first digit, 5 possibilities for the middle digit, and 2 for the last digit. The product is the number of integers that satisfy the preset conditions. \(4*5*2= 40 \)
Here is the second way by ElectricPavlov:
First digit cannot be 5 so yo have 4 * 5 * 5 possible numbers = 100
2 out of 5 will be even as 2 and 4 are the only evens 2/5 x 100 = 40 possibilities.
+285 Answer:
Nearest ten
Step-by-step explanation:
Here, we want to know the highest value that can be attained if this number is rounded up to the decimal places given in the question.
The best way to go about this is rounding this number to each of the decimal places and see the one that has the largest value.
We proceed as follows;
Nearest hundred = 300
Nearest ten = 350
Nearest integer = 346
Nearest tenth = 345.7
Nearest hundredth = 345.67
It can be seen from all the above values that the highest value we have is the nearest ten
I got this anwers from https://brainly.com/question/17117960
