If \(23=x^4+\frac{1}{x^4}\), then what is the value of \(x^2+\frac{1}{x^2}\)?
-hihihi
😎😎😎
x^2 + 1/x^2 square both sides
(x^2 + 1/x^2) ( x ^2 + 1/x^2) =
x^4 + x^2 (1/x^2) + x^2(1/x^2) + 1/x^4 =
x^4 + 1 + 1 + 1/x^4
x^(4) + (1/x^4) + 2 = 23 + 2 = 25
So
(x^2 + 1/x^)^2 = 25
x^2/ + 1/x^2 = 5 (assuming x is real)
CPhill that is correct
hihi,
CPhill is a mathematician.
A more appropriate response would have been :
"Thanks very much CPhill..
I never would have thought of that by myself. I hope next time I will be able to do a question like this by myself."
+285 
