$$|1-6| \equiv 2 (mod 3)$$
This is true because |1-6|=5
and 5 divided by 3 is 1 remainder 2
2 is the remainder.
Modular arithmetic is only concerned with the remainder.
So I could say that
|a-b|-3n=2 where $$n\in J \ge 0$$
It is meat or vegies or fruit wrapped in pastry.
That is an approximation Shaniab. :)
$$\\12x^2-5y^2=523 \qquad (1)\\ 6x^2+2y^2=482 \qquad \;\; (2) \rightarrow 12x^2+4y^2=964\qquad (2b)\\\\ (2b)-(1)\\\\ 4y^2-\;-5y^2=964-523\\ 9y^2=441\\ y=\pm 7$$
Can you finish it now?
It is even if f( x) = f (-x)
I'll look at the first one.
f(x)=(x+2)(x-2)
f(-x)=(-x+2)(-x-2)
f(-x)=-(-x+2)(x+2)
f(-x)=- - (x-2)(x+2)
f(-x)=+ (x+2)(x-2)
f(-x)=f(x)
SO YES the first one is even. :)
there are several ways I think
I'd press the [LaTex Formula] button and write something like \sqrt[3]{15} and then press OK
$$\sqrt[3]{15}$$ This is what I got.
Does that help? Have a play with it you can do a lot ot things with LaTex.
use the site calc of is multiply
the first number divided by the second number multiplied by 100 then put the percent sign when you write it down.
What expression?
73^73 from the site calc is 1.0533405146807287 x 10^136
+118735 
