Melody

Thank you anon - I really like it that you have gotten involved.   

Yes, I think Chris is right

$${factor}{\left({\mathtt{144}}\right)} = {{\mathtt{2}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{{\mathtt{3}}}^{{\mathtt{2}}}$$

1^1=1

2^2=4

3^2=9

(2*2)^2=16

(2*3)^2=36

(2^2*3)^2=(4*3)^2=144

y=-1/2sin[4(x+pi/4)]+1

You can build these up bit by bit.  You DO need to know what y=sinx looks like

y=sinx  has a frequency of 2pi    

y=sin4x  Will have a frequency of  2pi/4

The point (0,0) on the curve sin4x will be moved to (-pi/4,0) on sin(4(x+pi/4)

That is, the phase shift will be pi/4 to the left.

y=sinx has an amplidude of 1. It oscilates between y=-1 and y=1    

y=1/2 sinx has an amplitude of 1/2

and y=-1/2sin x will reflect it across the x axis (turn it upside down)

 The plus one ar the end will lift the whole curve up by one.

So instead of it oscillating between y=-0.5 and 0.5  it will oscillate between y=0.5 and 1.5

I can show you these steps on a Desmos graph

I will only show the sine graph at the beginning then I will step through the building of the final graph one step at the time.

Each graph can be displayed (or made invisable again) by clicking the circle in front of its formula  

You made that look REALLY hard Heureka   LOL   :))

That is great Heureka    

You cannot take the log of a negative number.

That is great MG.

So you obviously do understand that area is how many squares fit inside a 2 dimensional shape :)

Please copy and paste the questions so that it all stays together with your answers :)

Try very hard to answer the exact question that I have asked :) This is one reason why students lose marks.  They do not answer the exact question that is asked :)

Question 1

Look at this shape.  This is made up of cubic blocks  Each side is 1cm. 

What is the area of the front face? (include units)

How many cubes are in the front row?

How many rows of blocks are there counting back from the front row?

What is the volume of the prism?

Write a sentence as to why.

Question 2

What is this shape?

If you cut it anywhere, parallel to the front triangle side.  What will be the shape of the cross section?

What is the area of the front triangle? (Show working)

If this was made of mm^3 blocks (some would need to be cut up) How many cubes would be needed to cover the front face? 

How many rows of block triangles would you need to make the whole shape?

What is the volume of this shape? (Show working)

How many mm^3 are there in a cm^3?      You have to show your working.

How many cm^3 are there in the above shape?  Please do it 2 ways and check that your answers are the same. :)

arc sine is the same as inverse sine.

so use    [2nd] [asin]

Hi Mellie,

Thanks for the points:)

Did you understand our answers ?

Ok so there are 6 male  and 4 female to choose from.

P(at least 4 males) = 5*(6/10)*(5/9)*(4/8)*(3/7)*(4/6) + (6/10)*(5/9)*(4/8)*(3/7)*(2/6)

$${\mathtt{5}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{6}}}{{\mathtt{10}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{9}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{4}}}{{\mathtt{8}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{3}}}{{\mathtt{7}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{4}}}{{\mathtt{6}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{6}}}{{\mathtt{10}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{9}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{4}}}{{\mathtt{8}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{3}}}{{\mathtt{7}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{6}}}}\right) = {\frac{{\mathtt{11}}}{{\mathtt{42}}}} = {\mathtt{0.261\: \!904\: \!761\: \!904\: \!761\: \!9}}$$