Melody

Where did your answer come from jdh3010?

$${\frac{{\mathtt{6}}}{{\mathtt{48}}}} = {\frac{{\mathtt{1}}}{{\mathtt{8}}}} = {\mathtt{0.125}}$$

Did you check that it is working jdh?    For a while it wasn't but it might be fixed now :/

Thanks Geno,

I do it the same as Geno but for me I must draw a triangle every time.

Then you can read the values of the triangle.  The only other thing you MUST consider is what quadrants it can be in and is the trig ratio going to be positive or negative or either.

If tanΘ=9/5, what is secΘ

tan is poitive so it must be in the 1st or third quadrant.

sec = 1/cos = hyp/adj   

cos and therefore sec will be positive in the 1st quad and negative in the 3rd quad. 

$$sec\theta = \frac{\pm\sqrt{106}}{5}$$

Our answers are different Geno, I think you have made a little mistake :)   $$sec\theta=\frac{1}{cos\theta}$$

I am going for NeoVoid's answer :)(

$$\\Y=\frac{6}{x}+19\\\\
$X cannot by 0 and Y cannot be 19$\\\\\\
\frac{6}{X}=Y-19\\\\
$ turn both sides upside down$\\\\
\frac{X}{6}=\frac{1}{Y-19}\\\\
$mult both sides by 6$\\\\
X=\frac{6}{Y-19}\\\\$$

Thanks Alan,

Here is a pic

there are 100cm in a 1 metre

so

there are $${{\mathtt{100}}}^{{\mathtt{2}}}$$  $${{\mathtt{cm}}}^{{\mathtt{2}}}$$    in     $${{\mathtt{1}}}^{{\mathtt{2}}}$$   $${{\mathtt{m}}}^{{\mathtt{2}}}$$

that is

$$10000\;cm^2\;=\;1\;m^2$$

$$\\11000m^2 = 10000\times 11000\;cm^2\\\\
11000m^2 = 110\;000\;000\;cm^2$$

(−1) x  ​494 = -494

$$\\\frac{(x^2-25)}{(x^2+7x+10)}\\\\
=\frac{(x-5)(x+5)}{(x+5)(x+2)}\\\\
x\ne-2\qquad and \qquad x\ne -5\\\\
=\frac{x-5}{x+2}\\\\$$