The is no ^0 in the original question.
I do not know what you have been eating but i don't want any. LOL
Anyway thanks DL for that great answer :))
Mmm, not quite right Dragonlance :)
$$\\-(4)^{-2}\\\\ =-(\frac{4}{1})^{-2}\\\\ =-(\frac{1}{4})^{+2}\\\\ =-(\frac{1^2}{4^2})\\\\ =-(\frac{1}{16})\\\\ =\frac{-1}{16}\\\\$$
YES of course you can.
The absolute value of a number is the distance it is from zero on the number line. :)
You can't solve it - it is not an equation or a question!
Rational numbers can be expressed as $$\frac{a}{b}$$ where a and b are integers and a and b have no common factors (except 1)
Irrational numbers cannot be expressed this way :)
well
$$\\a^3*a^7 = a^{3+7}\\\\so\\\\ a^{f(x)}*a^{g(x)}=a^{f(x)+g(x)}$$
k=inverse tan (z)
Bye Zegroes :))
if 2X=pi*10-0.5 what does x =
divide both sides by 2 :)
X= 5pi - 0.25
+118723 
