Melody

2-1.87  litres

you cannot simplify this unless s is given a number :)

Ok Dragonlance, I will let you know if you make a mistake. :))

Yes thank you Geno.  I would not have known how to do it either. 

I might have muffled through to an answer but it would not have been well organised like yours is. 

Thank you also Dragonlance for bringing Geno's answer to my attention!

I have put this in our "Reference material" sticky topic   threads   

That Reference thread really needs to be reorganised - any volunteers ? :))

1/ a half  = 2

[(x^2)-20x+(23/3)]'-√576+4!=0

$$\\\left(x^2-20x+\frac{23}{3}\right)-\sqrt{576}+4!=0\\\\
\left(x^2-20x+\frac{23}{3}\right)-24+24=0\\\\
x^2-20x+\frac{23}{3}=0\\\\
3x^2-60x+23=0\\\\
x=\frac{60\pm\sqrt{3600-276}}{6}\\\\
x=\frac{60\pm\sqrt{3324}}{6}\\\\
etc$$

Geno's answer is an OR

either of those statements will make the inequality true :)

Perhaps you should give us an example :)

$$\\0=a+\frac{8}{3}+\frac{1}{3}*a\\\\
0=a+\frac{8}{3}+\frac{a}{3}\\\\
0*3=3\left(a+\frac{8}{3}+\frac{a}{3}\right)\\\\
0=3a+8+a\\\\
0=4a+8\\\\
-8=4a\\\\
-2=a\\\\
a=-2$$

 [(x^2)-20x+(23/3)]'-√576+4!=0?

What is the apostrophy for?