Melody

You can cancel units in the same way that you can cancel numbers

you have  

$$\dfrac{19.3g}{cm}\qquad 4cm\qquad \mbox{and you want mass which is measured in grams}$$

$$\dfrac{19.3g}{cm}\times \dfrac{4cm}{1}\\\\
=\dfrac{19.3g}{\not{cm}}\times \dfrac{4\not{cm}}{1}\\\\$$

The cm cancel out leaving 19.3*4g = 77.2g

I do almost all rates like this.  

Thanks Alan but can you give an example of when my interpretation is wrong?

If they are not all true there will be a 0 on the mix. When multiplied the answer will be 0 so the answer will be false.

So it just means " A and B and C are all true."

And the answer is false ?

@@ End of Day Wrap - Monday  30/6/14   Sydney, Australia   Time 9:50pm   ♬ 

Hi everyone,

It was an extremely quiet day today.  Answers were given by CPhill, Henk1668, Rosala, CPhill, Pokemonfan58 and NinjaDevo.

NinjaDevo snuck in very quietly yesterday and earned himself a star.  Sorry Ninja, I didn't notice until today, you are very stealthy.   Anyway

♬         !!! CONGRATULATIONS NINJADEVO !!!          ♬           

Andre Massow has done some more work on the site, the look is just a little different.  these are tow differences that I have noticed.

•  There are now blue ticks on the answer page.

• The other language forums are now indicated by the language initials as before but also by national flags.  These can be found at the bottom of each page.  If you want to go to a different forum just click the appropriate portal and you will be whisked away.  You will have to sign in again though when you arrive.

• There are now 12 people on the Top Answerers board, before there were 10.  This means that Rosala and GoldenLeaf are now on the board.

♬         !!!  CONGRATULATIONS ROSALA AND GOLDENLEAF   !!!        ♬          

Andre Massow, Site Owner and Developer, has made it very clear that there is to be no religious material of any kind posted on this forum.         

That is all for today, thank you everyone,

Melody.

To me this question is nonsense but Alan already answered it anyway.

Added later: Boolean logic - yes I should have realised.

Well Alan, I have absoutely no idea what this question is about so I'll give you thumbs up for providing A answer.

Yours is actually very similar to Rosala's Henk1668.  Just remember that when you multiply by 100 you must not forget to add the % sign.  It is very important.

$$\begin{array}{rll}
a-3\times \left(\frac{-1}{2}\right)-\frac{1}{2}&=&0\\\\
a&=&3\times \left(\frac{-1}{2}\right)+\frac{1}{2}\\\\
a&=&\left(\frac{-3}{2}\right)+\frac{1}{2}\\\\
a&=&\frac{-3+1}{2}\\\\
a&=&\frac{-2}{2}\\\\
a&=&\;-1


\end{array}$$

$$\begin{array}{rll}
30000&=&15500(1+\frac{5.75}{4})^{4t}\\\\
\frac{30000}{15500}&=&(1+\frac{5.75}{4})^{4t}\\\\
\frac{60}{31}&=&(2.4375)^{4t}\\\\
log\left(\frac{60}{31}\right)&=&log\left(2.4375^{4t}\right)\\\\
log\left(\frac{60}{31}\right)&=&4t\;log \;2.4375\\\\
\dfrac{log\left(\frac{60}{31}\right)}{4log \;2.4375}&=&t\\\\

\end{array}$$

$${\frac{{log}_{10}\left({\frac{{\mathtt{60}}}{{\mathtt{31}}}}\right)}{\left({\mathtt{4}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{2.437\: \!5}}\right)\right)}} = {\mathtt{0.185\: \!291\: \!084\: \!619\: \!587\: \!8}}$$

Tues 30/6/14

♬                                        ♬ ♬ MELODY ♬ ♬

Reinout is back - Lunch box unwrap.