0=9(3-2 / 3)+33

This problem s simply asking you to simplify the other side to see if it equals zero. I think, I'm just assuming but just simplify the right side as much as you can nothing special.

$0=9\times(3-\frac{2}{3})+33$

$0≠9\times(3-\frac{2}{3})+33$

$0≠27-\frac{2}{3}+33$

$0≠\frac{81}{3}-\frac{2}{3}+33$

$0≠\frac{79}{3}+33$

$0≠\frac{79}{3}+\frac{99}{3}$

$0≠\frac{178}{3}$

$0≠ 59.3333333333333333...$