1+2+(2^2)+...+(2^(n-1)) = (2^n) -1

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1+2+(2^2)+...+(2^(n-1)) = (2^n) -1

Hello! I need help with the proof for this.

Guest Mar 16, 2015

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Best Answer

+33661

+5

Here's a direct proof:

geometric progression sum

(An alternative would be a proof by induction.)

.

Alan Mar 16, 2015

1⁺⁰ Answers

+33661

+5

Best Answer

Here's a direct proof:

geometric progression sum

(An alternative would be a proof by induction.)

.

Alan Mar 16, 2015

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