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15x^1/2y^1/12 / 24x^5/6y^1/6

 Jul 13, 2014

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 #1
avatar+118723 
+5

Your question needs brackets to make it unambiguous.

Is this is what you have asked.

 

$$15x^{1/2}y^{1/12}/(24x^{5/6}y^{1/6})\\\\
=\frac{15}{24}x^{1/2-5/6}y^{1/12-1/6}\\\\
=\frac{5}{8}x^{3/6-5/6}y^{1/12-2/12}\\\\
=\frac{5}{8}x^{-2/6}y^{-1/12}\\\\
=\frac{5}{8y^{1/3}y^{1/12}}$$

 Jul 13, 2014
 #1
avatar+118723 
+5
Best Answer

Your question needs brackets to make it unambiguous.

Is this is what you have asked.

 

$$15x^{1/2}y^{1/12}/(24x^{5/6}y^{1/6})\\\\
=\frac{15}{24}x^{1/2-5/6}y^{1/12-1/6}\\\\
=\frac{5}{8}x^{3/6-5/6}y^{1/12-2/12}\\\\
=\frac{5}{8}x^{-2/6}y^{-1/12}\\\\
=\frac{5}{8y^{1/3}y^{1/12}}$$

Melody Jul 13, 2014

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