17^(6v-1)>23^(4v+2)

the answer to your question is 8

04152552362

17^(6v-1)>23^(4v+2)     take the log of both sides

(6v - 1) log17  > (4v + 2) log 23   simplify

6v log 17 - log 17 > 4vlog 23 + 2log 23      rearrage and factor as

v [ 6 log 17 - 4 log 23]  > log17 + 2 log23    divide both sides by  6log 17 - 4 log 23

v  > [ log17 + 2log23 ] / [ 6 log 17 - 4log 23]

v > about  2.0425

thanks cphill u tha man